1/16x^2+x-5=0

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Solution for 1/16x^2+x-5=0 equation: 


x in (-oo:+oo)

(1/16)*x^2+x-5 = 0

1/16*x^2+x-5 = 0

DELTA = 1^2-(-5*1/16*4)

DELTA = 9/4

DELTA > 0

x = ((9/4)^(1/2)-1)/(1/16*2) or x = (-(9/4)^(1/2)-1)/(1/16*2)

x = 4 or x = -20

x in { -20, 4 }

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